19th June 2022 I Problems based on Tabular and Diagrammatical Data – Problems based on Probability Logical Reasoning, Analytical and Mental ability

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Number of questions- Prelims: 15

Prelims questions of the day- 

1.In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

  1. 1/3
  2. 3/5
  3. 8/21
  4. 7/21 

Answer: A

Explanation:

Total number of balls = (8 + 7 + 6) = 21.

Let E = event that the ball drawn is neither red nor green 

            = event that the ball drawn is blue.

n(E) = 7.

P(E) = n(E)/ n(S) = 7/21 = 1/3.

2.In a class, 30% of the students offered English, 20% offered Hindi and 10% offered both. If a student is selected at random, what is the probability that he has offered English or Hindi?

  1. ½
  2. ¾
  3. 4/5
  4. 2/5

Answer: D

Explanation:
P(E)=30/100=3/10

P(H)=20/100=1/5

P (E AND H) =10/100=1/10

P(E OR H)= P(E)+P(H)-P(E AND H)=(3/10)+(1/5)-(1/10)=4/10=2/5

3.Three unbiased coins are tossed. What is the probability of getting at most two heads?

  1. ¾
  2. 7/8
  3. ½
  4. ¼

Answer: B

Explanation:

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}

Let E = event of getting at most two heads.

Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.

P(E) =n(E)/n(S)=7/8.

4.What is the probability of getting a sum 9 from two throws of a dice?

  1. 1/2
  2. ¾
  3. 1/9
  4. 2/9

Answer: C

Explanation:

In two throws of a die, n(S) = (6 x 6) = 36.

Let E = event of getting a sum ={ (3, 6), (4, 5), (5, 4), (6, 3)}.

P(E) =n(E)/n(S)=4/36=1/9.

5.What is the probability of getting 53 Mondays in a leap year?

  1. 1/7
  2. 3/7
  3. 2/7
  4. 1

Answer: C

Explanation:

1 year = 365 days. A leap year has 366 days

A year has 52 weeks. Hence there will be 52 Sundays for sure.

52 weeks = 52 x 7 = 364days

366 – 364 = 2 days

In a leap year there will be 52 Sundays and 2 days will be left.

These 2 days can be:

1. Sunday, Monday

2. Monday, Tuesday

3. Tuesday, Wednesday

4. Wednesday, Thursday

5. Thursday, Friday

6. Friday, Saturday

7. Saturday, Sunday

Of these total 7 outcomes, the favourable outcomes are 2.

Hence the probability of getting 53 days = 2/7

6.Out of 17 applicants 8 boys and 9 girls. Two persons are to be selected for the job. Find the probability that at least one of the selected persons will be a girl?

  1. 19/34 
  2. 5/4 
  3. 20/34 
  4. 25/34

 Answer: D

Explanation:

The events of selection of two person is redefined as first is a girl and second is a boy or first is boy and second is a girl or first is a girl and second is a girl.

So the required probability:

= (817*916)+(917*816)+(817*716)817*916+917*816+817*716

=934+934+734934+934+734
= 2534

7.There are four hotels in a town. If 3 men check into the hotels in a day, then what is the probability that each checks into a different hotel?

  1. ½
  2. ¾
  3. 4/7
  4. 3/8

Answer: D

Explanation:

Total cases of checking in the hotels = 4 x 4 x 4 = 64 ways.

Cases when 3 men are checking in different hotels = 4×3×2 = 24 ways.

Required probability =24/64 = 3/8

8.A speaks truth in 75% of cases and B in 80% of cases. In what percentage of cases are they likely to contradict each other, narrating the same incident?

  1. 30/100
  2. 35/100
  3. 45/100
  4. 50/100

Answer: B

Explanation:

Let   A = Event that A speaks the truth

B = Event that B speaks the truth

Then P(A) = 75/100 = 3/4

P(B) = 80/100 = 4/5

P(A-lie) = 1−341-34= 1/4 

P(B-lie) = 1−451-45= 1/5 

Now, A and B contradict each other = [A lies and B true] or [B true and B lies]

 = P(A). P(B-lie) + P(A-lie). P(B) 

 = (35*15) +(14*45) =72035*15+14*45=720  

 = (720*100)720*100= 35%

9.In a simultaneous throw of pair of dice. Find the probability of getting the total more than 7?

  1. ½
  2. 5/12
  3. 7/15
  4. 3/12

Answer: B

Explanation:

Here n(S) = (6 x 6) = 36

Let E = event of getting a total more than 7
        = {(2,6),(3,5),(3,6),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5),(6,6)}

Therefore, P(E) = n(E)/n(S) = 15/36 = 5/12.

10.If two letters are taken at random from the word HOME, what is the probability that none of the letters would be vowels?

  1. 1/6
  2. ½
  3. 1/3
  4. ¼

Answer: A

Explanation:

P (first letter is not vowel) = 2/4

 P (second letter is not vowel) = 1/3

 So, probability that none of letters would be vowels is = (2/4) ×(1/3)=1/6

Directions : Study the following pie charts carefully and answer the questions given beside. The pie charts represent the percentage distribution of the bags which have been sold and supplied in a bag market in 7 different cities in year 2016 and 2017, respectively.

Total number of bags sold and supplied in 2016 = 87600

Total number of bags sold and supplied in 2017 = 96900

2016

data interpretation for sbi clerk and ibps clerk 2019

2017
data interpretation for sbi clerk and ibps clerk 2019

1.What is the difference between the total number of bags sold and supplied in Kota in 2016 and the total number of bags sold and supplied in Kota in 2017?

  1. 509
  2. 549
  3. 639
  4. 519

Answer: D

Explanation:

The total number of bags sold and supplied in Kota in 2016

=16% of 87600=14016

The total number of bags sold and supplied in Kota in 2017

=15%  of 96900=14535

Therefore, required difference = 14535 – 14016 = 519

2.What is the ratio of the number of bags sold and supplied in Mumbai bag market in 2016 and the number of bags sold and supplied in Mumbai bag market in 2017?

  1. 1533: 1615
  2. 1142: 1243
  3. 1447: 1589
  4. 1321: 1541

Answer: A

Explanation:

The total number of bags sold and supplied in Mumbai bag market in 2016

21% of 87600=18396

The total number of bags sold and supplied in Mumbai bag market in 2017

=20% of 96900=19380

Therefore, reqd. ratio = 18396 = 1533
193801615

3.The total number of bags sold and supplied in Raipur in 2016 is approximately what percent of the total number of bags sold and supplied in Raipur in 2017?

  1. 72.4%
  2. 73.8%
  3. 77.2%
  4. None of these

Answer: D

Explanation:

The total number of bags sold and supplied in Raipur bag market in 2016

5% of 87600=4380

The total number of bags sold and supplied in Raipur bag market in 2017

=6% of 96900=5814

Therefore, reqd. percentage = 4380 × 100 = 75.3%
5814

4.The total number of bags sold and supplied in Nagpur and Raigarh together in 2017 is approximately what percent of the total number of bags sold and supplied in Nagpur and Calcutta together in 2016?

  1. 117.7%
  2. 110.6%
  3. 106.3%
  4. 114.4%

Answer: B

Explanation:

The total number of bags sold and supplied in Nagpur and Calcutta bag market in 2016

=(13+8)% of 87600=18396

The total number of bags sold and supplied in Nagpur and Raigarh bag market in 2017

(13+8) % of 96900=20349

Therefore, reqd. percentage = 20349 × 100 = 110.6%
18396


5.The manufacturing charge per bag in Delhi was Rs. 9000 in 2016 while Rs. 11000 in 2017. Find the difference between the total manufacturing charge incurred by the bag market in 2016 and 2017 from Delhi Bag Market.

  1. Rs. 113788000
  2. Rs. 118216000
  3. Rs. 104127000
  4. Rs. 121456000

Answer: C

Explanation:

The total number of bags sold and supplied in Delhi bag market in 2016 

26% of 87600=22776

Total charge incurred by Delhi bag market in 2016 = 22776 × 9000 = Rs. 204984000

The total number of bags sold and supplied in Delhi bag market in 2017

29% of 96900=28101

Total charge incurred by Delhi bag market in 2017 = 28101 × 11000 = Rs. 309111000

Therefore, required difference = 309111000 – 204984000 = Rs.104127000

Hence, option C is correct.

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